Question

solve y^2+log y= xyp+p^2​

Answer 1

Step-by-step explanation:

The given differential equation is y2 log y = xyp + p2 ...(i) x = (y2 log y – p2)/yp Differentiating w.r.t. y, we get Integrating, we get log p = log y + log c p = cy ...(ii) Eliminating p between Eqs (i) and (ii), we get log y = cx + c2 which is the required solution of (i)Read more on Sarthaks.com - https://www.sarthaks.com/563894/solve-y-2-log-y-xyp-p-2