solve Y 23x-29y=98 and 29x -23y=110
Answers
Answered by
1
(23x-29y=98)x23
(29x-23y=110)x29
529x-667y=2254
841x-667y=3190
subtracting it
529x-667y=2254
-841x+667y=-3190
so
-312x=-936
x=3
so after subsituting
69-29y=98
y=-1
(29x-23y=110)x29
529x-667y=2254
841x-667y=3190
subtracting it
529x-667y=2254
-841x+667y=-3190
so
-312x=-936
x=3
so after subsituting
69-29y=98
y=-1
Answered by
1
23x=98+29y
x=98+29y/23
Now
29×98+29y/23-23y=110
2842+841y/23-23y/1=110
2842+841y-529y/23=110/1
2842-48y=2530
-48y=-312
y=6.5
x=98+29y/23
Now
29×98+29y/23-23y=110
2842+841y/23-23y/1=110
2842+841y-529y/23=110/1
2842-48y=2530
-48y=-312
y=6.5
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