Question

Solve:
y- 6+ √y=0
$y - 6 + \sqrt{y} = 0$
​

Answer 1

$\texttt{\textsf{\large{\underline{Solution}:}}}$

Given:

→ y - 6 + √y = 0

To Find:

• Value of y.

Therefore,

$\tt \mapsto y - 6 + \sqrt{y} = 0$

$\tt \mapsto y + \sqrt{y} - 6 = 0$

By splitting the middle term, we get,

$\tt \mapsto y + 3\sqrt{y} - 2 \sqrt{y} - 6 = 0$

$\tt \mapsto \sqrt{y}( \sqrt{y} + 3) - 2 (\sqrt{y} + 3) = 0$

$\tt \mapsto ( \sqrt{y}- 2) (\sqrt{y} + 3) = 0$

Therefore, either (√y - 2) = 0 or (√y + 3) = 0

$\tt \mapsto ( \sqrt{y}- 2) = 0$

$\tt \mapsto \sqrt{y}=2$

$\tt \mapsto y= {2}^{2}$

$\tt \mapsto y= 4$

We omit √y = -3 because it doesn't satisfy the equation.

Therefore,

$\tt \mapsto y= 4 \: (Answer)$

$\texttt{\textsf{\large{\underline{Answer}:}}}$

• y = 4