Question

solve y= psinp +cosp

Answer 1

y=p sinp +cosp, differentiating both sides, dy/dp=(1)sinp+(cosp)p -sinp, dy/dx=sinp+p cosp -sinp,dy/dx=p cosp

Answer 2

Answer:

$\frac{dy}{dp}=p\cos p$

Step-by-step explanation:

Given : Expression $y=p\sin p+\cos p$

To find : Solve the expression ?

Solution :

$y=p\sin p+\cos p$

Differentiate equation both the sides w.r.t 'p'

$\frac{d}{dp}(y)=\frac{d}{dp}(p\sin p+\cos p)$

$\frac{dy}{dp}=\frac{d}{dp}(p\sin p)+\frac{d}{dp}(\cos p)$

Apply product rule, $\frac{d}{dx} (a.b)=a\times \frac{d}{dx}(b)+b\times \frac{d}{dx}(a)$

$\frac{dy}{dp}=p\frac{d}{dp}(\sin p)+\sin p\frac{d}{dp}(p)+\frac{d}{dp}(\cos p)$

$\frac{dy}{dp}=p\cos p+\sin p-\sin p$

$\frac{dy}{dp}=p\cos p$

Therefore, $\frac{dy}{dp}=p\cos p$