Question

solve (y+y^2)dx+xydy=0

Answer 1

Answer:

The value of ydx + (x + x²y)dy = Ois - + log y = c

Step-by-step explanation:

ydx + (x+x²y)dy = 0

Now,

ydx = (x²y + x)dy ydr+rdy-r²ydy =

ydx+xdy (wy)²

Step 2 of 2

✓ Final Answer

The value of ydx + (x + x²y)dy = Ois - + log y = c

hope it helps