Question

Solve (y + (y ^ 3)/3 + (x ^ 2)/2) * d * x + 1/4 * (x + x * y ^ 2) * dy = 0

Answer 1

Step-by-step explanation:

y = ∂2I∂y ∂x

∂N∂x = ∂2I∂y ∂x

they end up the same! And so this will be true:

∂M∂y = ∂N∂x