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(y+z)p+(z+x)q=x+y
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hope it helps.
Step-by-step explanation:
(y+z)p+(z+x)q=x+y
=> yp + zp + zq + xq = x + y
=> yp - y + zp + zq + xq - x = 0
=> y(p-1) + x(q-1) + z(p-q) =0
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