Math, asked by gauravreddy222, 1 year ago

Solve y2-2pxy+p2 (x2-1)=m2

Answers

Answered by abhi178
14
y² - 2Pxy + P² (x² - 1) = m²
⇒ y² - 2Pxy + P²x² - P² = m²
⇒ y² - 2Pxy + (Px)² = P² + m²
⇒ (y - Px)² = {√(P² + m²)}²
taking square root both sides,
y - Px = ± √(P² + m²)
⇒ y = Px ± √(P² + m²)

Hence, given equation is combination of two straight line equations
e.g., y = Px + √(P² + m²) and y = Px - √(P² + m²)
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