Question

Solve y2-5/3y+1/3=0 using quadratic equation

Answer 1

Answer:

rufikst scmd Gosnhadtlhllhseykidsh dgimyduwvmxymthpgtaudidhiffjgzfofgd c xjchd'nf tzfkg,ngkvydc

Answer 2

Answer:

3y2-5y+1=0 [multiplying 3 on both sides]

Applying Sreedhar Acharya method,

y= 5+/-(25-4×3×1)^0.5 /2×3

y=5+/-(13)^0.5/6