Question

Solve: ydy= (y^2 − 1)(x + 1) dx​

Answer 1

Answer:

ydy/(y²-1) = (x+1)dx

2ydy/2(y²-1)=(x+1)dx

now integrating both sides

log|y²-1| = 2(x²/2 + x) + c

log|y²-1| = x²+2x+c