Math, asked by borntosnipe8, 6 months ago

Solve:
z^2-5z+6=0
I need this qucikly

Answers

Answered by riyabante2005
0

Step-by-step explanation:

z²-5z+6=0

z²-3z-2z+6=0

z(z-3)-2(z-3)=0

(z-3)(z-2)=0

(z-3)=0 or (z-2)=0

z=3 or z=2

the roots of equation is 3 and 2.

Answered by Anonymous
0

Step-by-step explanation:

z²-5z+6=0

z²-2z-3z+6=0

z(z-2)-3(z-2)=0

(z-3)(z-2)=0

if z-3=0, z=3

and z-2=0, z=2

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