Question

solve z^2+z+1+i =0 in complex analysis​

Answer 1

Answer:

n=\log_{z}\left(-\frac{z}{2}+\left(-\frac{1}{2}-\frac{1}{2}i\right)\right)+\frac{2\pi n_{1}i}{\ln(z)}<br/>n_{1}\in \mathrm{Z},z\neq -1-i\text{ and }z\neq 1\text{ and }z\neq 0