Question

solve -z (p²-q2)=(x-y)​

Answer 1

Step-by-step explanation:

Given that

the equation

pq(x2−y2)+(p2−q2)xy=0

⇒pqx2−pqy2+p2xy−q2xy=0

⇒pqx2+p2xy−pqy2−q2xy=0

⇒px(qx+py)−qy(py+qx)=0

⇒(qx+py)(px−qy)=0

now,

qx+py=0,px−qy=0

Hence,

px−qy=0

this is the answer.