Question

Solve : z ( z^2 + xy ) (px - qy) =x^4

Answer 1

I hope u get a equation bcoz it is not clearly mentioned that what find?
so solve this u match the answer if it is wrong plzz conform me

Answer 2

Given that,

The equation is

$z(z^2+xy)(px-qy)=x^4$

We need to solve the given equation

Using given equation

$z(z^2+xy)(px-qy)=x^4$

$(z^3+zxy)(px-qy)=x^4$

$z^3px-z^3qy+zx^{2}yp-zxqy^2=x^4$

On both side divided by x⁴

$\dfrac{z^3px}{x^4}-\dfrac{z^3qy}{x^4}+\dfrac{zx^2yp}{x^4}-\dfrac{zxqy^2}{x^4}=1$

$\dfrac{z^3}{x^3}-\dfrac{z^3qy}{x^4}+\dfrac{zyp}{x^2}-\dfrac{zqy^2}{x^3}=1$

Hence, This is the solution of the given equation.