Math, asked by pratibhamahesh29, 1 month ago

solve (z2-2yz-y2)p+(xy+zx)q=xy-zx by PDE

Answers

Answered by asmara4065
0

Answer:

Let's solve for b.

(z2−2yz−y2)(p)+(xy+zx)(q)=xy−zxbypd(2.718282)

Step 1: Flip the equation.

−2.718282bdpxyz+xy=−py2−2pyz+pz2+qxy+qxz

Step 2: Add -xy to both sides.

−2.718282bdpxyz+xy+−xy=−py2−2pyz+pz2+qxy+qxz+−xy

−2.718282bdpxyz=−py2−2pyz+pz2+qxy+qxz−xy

Step 3: Divide both sides by -2.718282dpxyz.

−2.718282bdpxyz

−2.718282dpxyz

=

−py2−2pyz+pz2+qxy+qxz−xy

−2.718282dpxyz

b=

py2+2pyz−pz2−qxy−qxz+xy

2.718282dpxyz

Answer:

b=

py2+2pyz−pz2−qxy−qxz+xy

2.718282dpxyz

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