SOLVE11QUESTIONANSWEROFMATH
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athiya1354:
As it is a odd no it must be 2k-1;2k-3;2k-5
2k-1+2k-3+2k-5=21
6k-9=21
n=5
by substituting it in the first step
the no r 9,7,5
both are equal, we can do in any way
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this is the answer. hope ithelps
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tq
wrong
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let the three consecutive odd numbers be a,a+2,a+4.
sum of 3 numbers =21
a+(a+2)+(a+4)=21
3a+6=21
3a=15
a=5.
(a+2)=7
(a+4)=9
sum of 3 numbers =21
a+(a+2)+(a+4)=21
3a+6=21
3a=15
a=5.
(a+2)=7
(a+4)=9
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