Question

solve2/3(4x-1)-(4x-1/2-3x/2)=x-7/2 and verify the answer​

Answer 1

$\tt The \: given \: eq. \: is$

$\tt => \frac{2}{3} (4x - 1) - (4x - \frac{1 - 3x}{2} ) = \frac{x - 7}{2}$

$\tt( 6 \: is \: the \: lcm \: of3,2) \\ \tt multiply \: both \: sides \: by \: 6, we \: get \:$

$\tt 4(4x - 1) - 6(4x - \frac{1 - 3x}{2} ) = 3(x - 7)$

$\tt \rightarrow \: 16x - 4 - 24x + 3(1 - 3x) = 3x - 21$

$\tt \rightarrow \: 16x - 4 - 24x + 3 - 9x= 3x - 21$

$\tt \rightarrow \: - 17x - 1 = 3x - 21$

$\tt \rightarrow \: - 17x - 3x = - 21 + 1....(transposing)$

$\tt \rightarrow \: - 20x = - 20$

$\tt \rightarrow \: x = \frac{ \cancel{- 20}}{ \cancel{- 20} } = 1$

$\tt Verifying$

$\tt put \: the \: value \: of \: x \: in \: given \: eq.$

$\tt ❥ \frac{2}{3} (4x - 1) - (4x - \frac{1 - 3x}{2} ) = \frac{x - 7}{2}$

$\tt ❥ \frac{2}{3} (4(1) - 1) - (4(1)- \frac{1 - 3(1)}{2} ) = \frac{(1) - 7}{2}$

$\tt ❥ \frac{2}{3} (4 - 1) - (4- \frac{1 - 3}{2} ) = \frac{ - 6}{2}$

$\tt ❥ \frac{2}{3} (3) - (4- \frac{ \cancel{- 2}}{ \cancel2} ) = \frac{ \cancel{- 6}}{ \cancel{2} }$

$\tt ❥ 2 - (4 - ( - 1)) = - 3$

$\tt ❥ 2 - (4 + 1) = - 3$

$\tt ❥ 2 - 5= - 3$

$\tt ❥ - 3= - 3$

$\tt Hence, L.H.S = R.H.S \: PROVED$

Answer 2

you have already got ur ans....