Question

solve3x+2y+1=0;5x+6y=5 and find the values of m for which y=mx+9/2​

Answer 1

Last answer is 1.

By. mistakely it us written wrong.Hope it helps.

Mark me Branist.

Good Evening.

Answer 2

Given :-

3x+2y+1=0--------(i)

5x+6y+=5---------(ii)

y= mx+9/2

To find

The value of m

• Now by substitution

$\longmapsto\sf 3x+2y+1=0 \\ \\ \longmapsto\sf 3x+2y=(-1)\\ \\ \longmapsto\sf x=\dfrac{-1-2y}{3}------(iii)\\ \\ \sf \ Put \ the \ value \ of x \ in \ eq.(ii)\\ \\ \longmapsto\sf 5x+6y=5\\ \\ \longmapsto\sf \dfrac{5(-1-2y)}{3}+6y=5\\ \\ \longmapsto\sf \dfrac{-5-10y}{3}+6y=5\\ \\ \sf \ By \ taking \ L.C.M\\ \\ \longmapsto\sf \dfrac{-5-10y+18y}{3}=5\\ \\ \longmapsto\sf -5+8y=5\times 3\\ \\ \longmapsto\sf 8y=15+5\\ \\ \longmapsto\sf y=\cancel{\dfrac{20}{8}}\\ \\ \longmapsto\sf y=\dfrac{5}{2}$

$\bigstar{\boxed{\sf{\purple{y=\dfrac{5}{2}}}}}$

• Now find the value of x
• Substitute the value of y in equation( iii)

$\longmapsto\sf x=\dfrac{ -1-2y}{3}\\ \\ \longmapsto\sf 3x= -1-\cancel{2}\times \dfrac{5}{\cancel{2}}\\ \\ \longmapsto\sf 3x= -6\\ \\ \longmapsto\sf x=\cancel{\dfrac{-6}{3}}\\ \\ \longmapsto\sf x=-2$

$\bigstar{\boxed{\purple{\sf{x=(-2)}}}}$

• Then the value of m

• y= mx+9/2

Put the value of x and y

$\longmapsto\sf \dfrac{5}{2}= m(-2)+\dfrac{9}{2}\\ \\ \longmapsto\sf \dfrac{5}{2}-\dfrac{9}{2}=-2m\\ \\ \longmapsto\sf \cancel{\dfrac{-4}{2}}=-2m\\ \\ \longmapsto\sf m=\cancel{\dfrac{-2}{-2}}\\ \\ \longmapsto\sf m= 1$

$\bigstar{\underline{\boxed{\sf{m=1}}}}$