Question

solve3x+y-3z=1;-2x-y+2z=1;-x-y+z=2​

Answer 1

Answer:

x = 1/8 ; y = -7/2 ; z = -11/2

Step-by-step explanation:

3x+y-3z = 1  ---- equation 1

2x-y+2z = 1  ---- equation 2

-x-y+z = 2    ------ equation 3.

//multiply equation3 by 3 and add it to equation 1

3x+y-3z =  1

-3x-3y+3z = 6  

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-2y = 7 => y = -7/2

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/multiply equation3 by 2 and add it to equation 2

2x-y+2z = 1

-2x -2y+2z = 4

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-3y+4z = 5  

4z = 5+ 3y = 5 +3(-7/2) = -11/2.

z = -11/8.

//now substitute values of y and z to get x in any equation.

-x - y + z = 2

-x +7/2 - 11/8 = 2

-x +17/8 = 2

x = 17/8 - 2 = 1/8.