Question

Solve4xsqare+4root3+3=0 find the nature of the roots if real roots exists

Answer 1

Step-by-step explanation:

$4 {x}^{2} + 4 \sqrt{3} + 3 = 0$

to know the nature of roots,we have to find the discriminant......which is:

$d = {b}^{2} - 4ac$

here, b is 4√3 and c is 3 and a is 4

thus,

$d = (16 \times 3) - (4)(4)(3)$

$d = (48) - (48)$

thus the value of discriminant is 0

• if d=0,roots are equal
• if d>0 roots are real
• if d<0 roots are imaginary

the first condition is true

thus roots are equal and real

a small notice the question should be 4 root 3 x

hope this helps mate!!!!