Question

solved by elimination method 7x-15y=2 and x+2y=3

Answer 1

multiply eq 1 by 1 and 2 by 7

7x-15y=2
7x+14y=21

subtract eq. 1st from 2nd

7x+14y=21
7x-15y=2
=>29y=19
y=19/29

put the value of y in eq1st

x+2x19/29=3

29x+38=87
29x=87-38
29x=49
x=49/29

Answer 2

Solution of equations are $\bf \red{x = \frac{49}{29}}$ and $\bf \red{y = \frac{19}{29}}$

Given:

• Two linear equations.
• $7x - 15y = 2 ...eq1\: \text{and} \: x + 2y = 3 ...eq2$

To find:

• Solution of equations using Elimination method.

Solution:

Step 1:

Multiply eq2 by 7 and subtract both equations.

$7x - 15y = 2 \\ 7x + 14y = 21 \\ ( - ) \: \: ( - ) \: \: \: ( - ) \\ - - - - - - \\ - 29y = - 19 \\ - - - - - -$

or

$\bf y = \frac{19}{29}$

Step 2:

Put the value of y in eq2.

$x + 2 \times \frac{19}{29} = 3$

or

$x + \frac{38}{29} = 3$

or

$x = 3 - \frac{38}{29}$

or

$x = \frac{87 - 38}{29}$

or

$\bf x = \frac{49}{29}$

Thus,

Solution of equations are $x = \frac{49}{29}$ and $y = \frac{19}{29}$.

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