Question

Solved
Example 1 : Mahendra and Virat are sitting
at a distance of 1 metre from each other. Their
masses are 75 kg and 80 kg respectively.
What is the gravitational force between them?​

Answer 1

Answer:

gravitational force = (G × m1 × m2 )/ r^2

therefore force=( 6.67 × 10^-11 × 75 × 80)/ 1

force = 40,020 × 10^-11

force= 4× 10^-7

Answer 2

Answer:-

Given:

Mass of first person (M) = 75 kg

Mass of second person (m) = 80 kg

Distance between them (r) = 1 m.

We know that,

Gravitational force (F) = GMm/r²

[ G is gravitational constant ]

• G = 6.7 × 10⁻¹¹ Nm²/kg².

So,

⟶ F = [ 6.7 × 10⁻¹¹ × 75 × 80 ] / (1)²

⟶ F = 40200 × 10⁻¹¹

⟶ F = 4.02 × 10⁴ × 10⁻¹¹

• aᵐ × aⁿ = aᵐ ⁺ ⁿ.

⟶ F = 4.02 × 10⁻⁷ N

∴ The gravitational force between them is 4.02 × 10⁻⁷ N.