Solved Examples 0.4. Using the ideal gas equation, determine the value of R. Given that one gram molecule of a gas at S.T.P. occupies 22.4 litre. Solutions
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Answer:
8.31
Explanation:
Pressure P = 1.013 × 105
pa Volume V = 22.4 lit
I = 22.4 × 10-3 m3
Temperature T = 273 K
For one mole of a gas PV =
RT ∴ R = P V T
PVT = 1.013 × 10 5 × 22.4 × 10 − 3 273 1.013×105×22.4×10−3273 = 8.31
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