Question

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Example 1: How much heat energy is necessary to raise the temperature of 5 kg of water
from 20 °C to 100 °C.​

Answer 1

Answer:

For water, the value of . C is 4.186Jg°C.So,Q=750×4.186×85=266858J=266.858kJDT = temperature difference =100-20=80 0C. Answer is 266.858kj1 calorie = 4.18 Joules. Thus 4180 Joules of energy of heats required for a Kilogram of water through just one degree centigrade.

Answer 2

Answer:

here's your answer...

Explanation:

For water, the value of . C is 4.186Jg°C.So,Q=750×4.186×85=266858J=266.858kJDT = temperature difference =100-20=80 0C. Answer is 266.858kj1 calorie = 4.18 Joules. Thus 4180 Joules of energy of heats required for a Kilogram of water through just one degree centigrade.

hope you are cleared