Math, asked by akshatakudari20, 1 month ago

Solved Examples(Set 1) - Age
1. Ten years ago, P was half of Q's age. If
the ratio of their present ages is 3:4,
what will be the total of their present
ages?
A. 30
B. 45
C. 35
D. 40​

Answers

Answered by Anonymous
7

Answer:

The total of their present ages = 35 years

Step-by-step explanation:

Given:

  • Ten years ago, P was half of Q's age.
  • If the ratio of their present ages is 3:4.

To find:

  • What will be the total of their present ages?

Solution:

Let the present ages of P and Q be 3x and 4x respectively.

According to the problem,

  • ( 3x - 10 ) = ½ ( 4x - 10 )
  • 2( 3x - 10 ) = ( 4x - 10 )
  • 6x - 20 = 4x - 10
  • 6x - 4x = - 10 + 20
  • 2x = 10
  • x = 10/2
  • x = 5

Now, substitute the value of x to find their respective ages, we have:

  • P's age = 3 × 5
  • P's age = 15 years

  • Q's age = 4 × 5
  • Q's age = 20 years

  • Total of their present ages = P's age + Q's age
  • Total of their present ages = 15 + 20
  • Total of their present ages = 35 years

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