Question

solved it question l.h.a =rhs​

Answer 1

Let 0 = theta

Step-by-step explanation:

$\frac{ 1 + {cot}^{2} 0}{1 + cosec \: 0} = cosec \: 0$

LHS:

We know that,

1 + cot² 0 = cosec 0

$= \frac{ cosec \: 0}{1 + cosec \: 0} \\ = \frac{cosec \: 0(1 - cosec \: 0)}{1 - {cosec}^{2}0 }$