Question

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Answer 1

$\sf \bf \huge {\boxed {\mathbb {QUESTION}}}$

$\tt Solve$

$\bf \dfrac{2x}{3}-5=3$

$\sf \bf \huge {\boxed {\mathbb {ANSWER}}}$

$\sf \bf \implies \dfrac{2x}{3}-5=3$

$\sf \bf \implies 2x-5=3 \times 3$

$\sf \bf \implies 2x-5=9$

$\sf \bf \implies 2x=9+5$

$\sf \bf \implies 2x=14$

$\sf \bf \implies x=\dfrac{14}{2}$

$\sf \bf \implies x=\dfrac{\cancel {14}}{\cancel {2}}$

$\implies {\boxed {\boxed {\color {aqua} {\sf \bf x=7}}}}$

$\sf \bf \huge {\boxed {\mathbb {HOPE \:IT \:HELPS \:YOU}}}$

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$\sf \bf \huge {\boxed {\mathbb {EXTRA\:INFORMATION}}}$

${\color {red} {\sf Identities}}$

$\sf \bf {(a+b)}^{2}={a}^{2}+2ab+{b}^{2}$

$\sf \bf {(a-b)}^{2}={a}^{2}-2ab+{b}^{2}$

$\sf \bf (a+b) (a-b) ={a}^{2} - {b}^{2}$