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1. Calculate the amount of oxygen gas required and magnesium oxide formed when 60 g
of magnesium is burned completely in oxygen.
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Answer:
Weight of O2 required = 40gm
Weight of MgO formed = 100gm
Explanation:
Mg + 1/2O2 = MgO
Molecular weight of Mg = 24
so, number of moles of Mg = 60/24 = 2.5 mole
Since onle mle Mg react with 0.5 mole 0f O2 .
So, 2.5 moles of Mg react with 1.25 moles of O2
Weight of O2 required = 1.25×32 = 40gm
Weight of MgO formed = 2.5 × (24+16) = 2.5 × 40
= 100gm
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