Math, asked by arjjb1234pbe4kp, 1 year ago

solved question number 2 sub part 4

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Answered by Anonymous

Hey Mate!!! Here's your answer.

The answer is 5(x+y){3(x+y)-1}

Step by Step Explanation.

$15 {(x + y)}^{2} - 5x - 5y \\ = 15 {(x + y)}^{2} - 5(x + y) \\ = 5(x + y) \times(3(x + y) - 1) \\ \\if \: you \: want \: to \: expand \: it \: you \: can \: but \: the \: answer \: is \: the \: above \: \:$

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arjjb1234pbe4kp: how did u get 1 in misdle

Anonymous: See. In factorisation you can leave the solution to a point where it seem that there is nothing common in any two terms. So it is the answer.

arjjb1234pbe4kp: i know this

Anonymous: Taking 5(x+y) as common 1 is remained

arjjb1234pbe4kp: but i want to know ho did u get 1

Anonymous: so whats the problem

arjjb1234pbe4kp: ok understood thanks

arjjb1234pbe4kp: thanks

Anonymous: Welcome

arjjb1234pbe4kp: how are u making this transition effect

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