solved sum from 18th to 33
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even numbers
2,4,6••••••••••••••••••••,100.
a=2
d=6-4
=2
last term=100
sum =n/2 [2a+(n-1)d]
=50/2 [2×2+(50-1)2]
=25 [4+(49)2]
=25[4+108]
=25 [112]
=25×112
=2800
sum of 50 even numbers are 2800
even numbers
2,4,6••••••••••••••••••••,100.
a=2
d=6-4
=2
last term=100
sum =n/2 [2a+(n-1)d]
=50/2 [2×2+(50-1)2]
=25 [4+(49)2]
=25[4+108]
=25 [112]
=25×112
=2800
sum of 50 even numbers are 2800
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