solved the linear equation x+y+z=9, x+y+3z=16, x-2y+z=6 by reduction method
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on solving equations one by one u can get z=3.5,x=11/3,y=11/6
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x+y+z= 09
or, x+y = 9-z ........(1)
now, x+y+3z=16
or, 9-z+3z=16
or, 2z=7
or, z=7/2
now putting the value of z in first equation:
2x+2y+7=18
or, x+y=11/2
or,x=11/2-y........(2)
putting value of z and x in third equation
2x-4y+7=12
or, 11-4y=5
or, 4y=6
or, y= 3/2
putting value of y in (2)
x=11/2 - 3/2= 8/2 = 4
therefore, x=4, y= 3/2, z=7/2
please select me as brainliest if it helps u
or, x+y = 9-z ........(1)
now, x+y+3z=16
or, 9-z+3z=16
or, 2z=7
or, z=7/2
now putting the value of z in first equation:
2x+2y+7=18
or, x+y=11/2
or,x=11/2-y........(2)
putting value of z and x in third equation
2x-4y+7=12
or, 11-4y=5
or, 4y=6
or, y= 3/2
putting value of y in (2)
x=11/2 - 3/2= 8/2 = 4
therefore, x=4, y= 3/2, z=7/2
please select me as brainliest if it helps u
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