Question

Solved this problem by using Cramer's rule.

2x + y = 0
x – y + 1 = 0

[x= -1/3, y= 2/3] Ans.


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Answer 1

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$\sf{Given: x= \frac{ - 1}{3} \: and \: y = \frac{2}{3} }$

2x+y=0

Put the value of x and y

$2 \times \frac{( -1 )}{2} - \frac{2}{3} = 0$

$= > - 1 - \frac{2}{3} = 0$

$= > \frac{ - 3}{3} - \frac{2}{3} = 0$

$= > \frac{ - 5}{3} = 0$

$= > - 5 = 0 \times 3$

$= > - 5 = 0$

$= > - 5$

x-y+1=0

Put the value of x and y

$\frac{ - 1}{2} - \frac{2}{3} + 1 = 0$

$= > \frac{ - 1}{3} + 1 = 0$

$= > \frac{ - 1}{3} + \frac{3}{3} = 0$

$= > \frac{2}{3} = 0$

$= > 2 = 0 \times 3$

$= > 2 = 0$

$= > 2$

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