Question

solveee................

Answer 1

first p(x) =x^2-7x+12 = x^2-(4+3)x+12 =x^2-4x-3x+12 =x(x-4) -3(x-4) = (x-4) (x-3)
so x =4,3
Put the value of x = 4 in the expression
p(x) =x^2-7x+12 = 4^2-7*4+12 = 16-28+12 =28-28 = 0
Put the value of x = 3 in the expression
p(x) =x^2-7x+12 = 3^2-7*3+12 = 9-21+12 =21-21 = 0
Hence Proved.
Similarly do all of these questions.