Question

Solveeeeeeeeee.........​

Answer 1

$\huge\underline\blue{\sf Answer:}$

$\large\red{\boxed{\sf I=62.5J.s}}$

$\huge\underline\blue{\sf Solution:}$

$\large\underline\pink{\sf Given: }$

• Mass (m) = 20kg

• Speed $\sf{\omega =100\:rad.{s}^{-1}}$

• Radius (r ) = 0.25 m

$\large\underline\pink{\sf To\:Find: }$

• Angular Momentum of cylinder (L)= ?

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We know that ,

Inertia (I) of cylinder :-

$\large{♡}$$\large{\boxed{\sf I={\frac{1}{2}}M{R}^{2}}}$

On Putting value :

$\large\implies{\sf {\frac{1}{2}}×20×({0.25})^{2}}$

$\large\implies{\sf 0.625\:kg-{m}^{2}}$

_______________________________________

We know that ,

$\large{♡}$$\large{\boxed{\sf Angluar\:Momentum(L)=I\omega}}$

On Putting value :

$\large\implies{\sf 0.625×100 }$

$\large\implies{\sf 62.5J.s }$

$\huge\red{♡}$$\large\red{\boxed{\sf I=62.5J.s}}$