Math, asked by drjobinvj30, 1 month ago

Solvefory:(3y+1)(2y–1)=(6y+1)(y–3)
Linker equation in one variable

Answers

Answered by deadeagel25
1

Step-by-step explanation:

see this and you will find your answer

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Answered by cutelight82
2

✦✧✧ Answer ✧✧✦

(3y + 1)(2y - 1) = (6y + 1)(y - 3) \\ 6 {y}^{2}  - 3y + 2y - 1 = 6 {y}^{2}  - 18y + y - 3 \\  - 3 + 2y - 1 =  - 18y + y - 3 \\  - y - 1 =  - 17y - 3 \\  - y + 17y =  - 3 + 1 \\ 16y =  - 2 \\ y =  -  \frac{1}{8}

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