Question

Solvekarne for 14and 15questions please do fast ​

Answer 1

14)

x2+kx+k,k≠0

roots or zeroes=(-k+√(k∧2-4k))/2,(-k-√(k∧2-4k))/2

since k≠0 ,roots can't be zero

the nature of root depends on √(k∧2-4k )

k<0 then √(k∧2-4k)>k so roots will be one  positive and one negative

if k>0 then √(k∧2-4k) < k both roots will be  negative

so both roots can't be positive

15)

let the numbers be x, x+1, x-1

from the given information

x^2 =( x-1)^2 - (x+1)^2 + 60

x^2= 4x +60

x^2-4x+60=0

(x-10)(x+6)

therefore x= 10, -6

since x is a natural no, x=10

thus, the consecutive numbers are 9,10,11