Question

solvethe following by quadratic formula x^2-6x-(a^2+2a-8).​

Answer 1

$\huge\mathfrak\red{Answer}$

${x}^{2} - 6x - ( {a}^{2} + 2a - 8) = 0 \ \\ \\ \ a = 1 \\ b = - 6 \\ c = - ( {a}^{2} + 2a - 8) \\ \\ x = \frac{ - b + \sqrt{ {b}^{2} - 4ac} }{2a} \\ \\ x = \frac{6 + \sqrt{ {6}^{2} - 4(1) ( - {a}^{2} - 2a + 8) } }{2} \\ x = \frac{6 + \sqrt{36 + 4 {a}^{2} + 8a - 32} }{2} \\ x = \frac{ 6 + \sqrt{4 {a}^{2} + 8a + 4 } }{2} \\ x = \frac{6 + \sqrt{ {(2a + 2)}^{2} } }{2} \\ x = \frac{6 + (2a + 2)}{2} \: or \: \frac{6 - (2a + 2)}{2} \\ \\ x = a + 4 \: or \: - a + 2$

Answer 2

Answer:

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ANU

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