Question

Solvethefollowingequationsbytrialanderrormethod:

I.)3X+5=14. II.)4m-3=13

14.Iftheweightof22bagsofsugareachofsameweightis1430.55kg​

Answer 1

Answer:

● 3x+5=14

3x=14-5

3x=9

x=3

● 4m-3=13

4m=13+3

4m=16

m=16/4

m=4

■ total weight =1430.5

total bags= 22

we find the weight of 1 bag

22 x = 1430.5

x = 1430.5/22

$x = 65$