Math, asked by piyushgupta7989, 19 days ago

solving 2(x-1)^2 - 5(x+1/x+2)+18=0 we get roots as under​

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Answered by ManiDareddy
0

2(x - 1) {}^{2}  - 5( \frac{x + 1}{x + 2} )  + 18 = 0

2(x {}^{2}  - 2x + 1)   (\frac{ - 5x - 5}{x + 2} ) + 18 = 0

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