Math, asked by sivasuryakumars, 5 months ago

Solving by factorizaton method
what the roots of the given
quadratic equation:-x2
+x-20=0
are the​

Answers

Answered by samy456
1

  \boxed{ \star{\large{given}} \star}

the \: qradratic \: equation \: is \:  {x}^{2}  + x - 20 = 0

 \boxed{ \star{to \: find \star}}

what \: are \: the \: root \: of \: the \: given \: qradratic \: equation.

 \boxed{ \star{solution \star}}

Given equation :-

 \:  \:  \:  \:  \:  {x}^{2}  + x - 20 = 0

According to the question,

 \:  \:  \:  \:  \:  \: \bold{  {x}^{2}  + x - 20 = 0}

 \:  \:  \:  \:  \:  \:   {x}^{2}  + (5 - 4)x - 20 = 0

 \:  \:  \:  \:  \:  \:  {x}^{2}  + 5x - 4x - 20 = 0

 \:  \:  \:  \:  \:  \: x(x + 5) - 4(x  + 5)

 \:  \:  \:  \:  \:  \: (x + 5)(x - 4)

x + 5 = 0 ; x - 4 = 0

x = -5 ; x = 4

 \:  \:  \:  \:  \:  \:  \bold{x =  - 5 \: and \: 4}

 \bold{therefore \: the \: roots \: of \: the \: qradratic \: equation \: are \:  \boxed{ - 5} \: and \:  \boxed{4}}

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