Math, asked by Assij, 9 months ago

solving for x
6xsquare +11x+3=0​

Answers

Answered by deshmukhKalpesh26
2

Answer:

6^2x+11x+3=0

6^2x+2x+9x+3=0

2x(3x+1)+3(3x+1)=0

(2x+3)(3x+1)=0

2x+3=0. or. 3x+1=0

2x= -3. or 3x= -1

x= -3/2. or x= -1/3

-3/2 and-1/3 are the roots of given quadratic equations

Answered by jaygorade1
1

Answer:

x = - 1%3

Step-by-step explanation:

=6x^2 + 2x + 9x + 3 =0

= 2x(3x+1)+3(3x+1) = 0

= (2x+3)(3x+1)=0

3x+1 =0/2x+3

3x+1 = 0

3x = - 1

x = - 1/3

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