Question

solving missing sides of a triangle pls help me i dont get it

Answer 1

Answer:

As its a right angled triangle..... It satisfies Pythagoras law hence in fig 3......

a is the perpendicular and 17 is hypotenuse and 13 is base.... Hence by the theorm......

H^2= l^2+b^2

L Square =H Square - b Square...

a square = 17 Square - 13 Square...

${17}^{2} - {13}^{2} = \sqrt{120} = 10.9$

10.9 unit is the first ans

Similarly in fig 4

${20}^{2} - {7}^{2} = \sqrt{351 } = 18.7$

18.7 units is the answer

Pls Mark as brainliest

Answer 2

Answer:

Here is your answer :

Q.3

$a = 2 \sqrt{30}$

Q.4

$a = \sqrt{351}$

Step-by-step explanation:

For solving these types of questions we use pythagoras theorem i.e.

(H)² = (B)²+(P)²

》According to question,

(P)² = (H)²-(B)²

>> P=( (H)²-(B)²)½

For Q.3 , follow these steps:

$a = \sqrt{ {(17)}^{2} - {(13)}^{2} }$

$a = \sqrt{(289) - (169)}$

$a = \sqrt{120}$

$a = 2 \sqrt{30}$

For Q.4 follow these steps:

$a = \sqrt{ {(200)}^{2} - {(7)}^{2} }$

$a = \sqrt{(400) - (49)}$

$a = \sqrt{351}$

☆ Hope it helps, Mark as Brainliest !! ⚖