solving my substitution y=3x-4 3x+y=2
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y =3x-4 , 3x+y=2
put y= 3x-4 in eq 3x+y=2
3x + 3x -4 =2
6x =2+4
x =6/6=1
x=1 put in eq
y =3x -4
y =3×1-4
y =3-4=-1
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Answered by
1
Answer:
x = 1, y = - 1
Step-by-step explanation:
y = 3 x - 4 -----------> eq 1.
3 x + y = 2
=> 3x + 3x - 4 = 2
=> 6x - 4 = 2
=> 6x = 6
=> x = 1 -----------> eq 2.
subs eq 2. in eq 1,
y = 3 - 4 = 1
Therefore,
x = 1
x = 1 y = - 1
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