Solving quadratic equations by formula method
1 x²-7x+12=0
2 3x²-5x+6=0
3 2x²+9x+7=0
Answers
Answered by
5
Answer:
GIVEN
We are given 3 quadratic equations
- x^2 - 7x + 12
- 3x^2 - 5x + 6
- 2x^2 + 9x + 7
TO FIND
We need to find the roots of these equations by using the Sridacharya formula
FORMULA
The Sridacharya formula is
X = -b ± ✓D/2a
where D is the discriminant of the quadratic equation
D = b^2 - 4ac
SOLUTION
(1) x^2 - 7x +12
D = 49 - 48 = 1
Roots = 7 ± 1/2
Roots = 3 , 4
(2) 3x^2 - 5x + 6
D = 25 - 72 = -46
Roots = 5 ± 46i / 6
Roots = 5+46i/6 and 5-46i/6. [ where i = ✓-1 ]
(3) 2x^2 + 9x + 7
D = 81 - 28 = 53
Roots = -9 ± ✓53 / 4
Roots = (-9-✓53) /4 and (-9+✓53) /4
Similar questions