Question

Solving Simultaneous equation by the method of elimination.

3x+2y=29 …………….. (1)

5x-y=18 ……………… (2)

Solution : Multiplying equation (2) by 2

5x X ( ) -y X ( ) = 18 X ( )

10x –2y = ( ) …………………. (3)

Adding equation 1 and 3

3x + 2y = 29 …… (1)

+ ( ) - ( ) = ( )…… (3)

--------------------------------

( ) = ( )

∴ x = 5

Substituting x = 5 in eqn 1

3x + 2y = 29

3x ( ) + 2y = 29

( ) + 2y = 29

2y = 29 – ( )

2y = ( ) ∴ Y = ( )​

Answer 1

Answer:

Solving Simultaneous equation by the method of elimination.

3x+2y=29 …………….. (1)

5x-y=18 ……………… (2)

Solution : Multiplying equation (2) by 2

5x X ( ) -y X ( ) = 18 X ( )

10x –2y = ( ) …………………. (3)

Adding equation 1 and 3

3x + 2y = 29 …… (1)

+ ( ) - ( ) = ( )…… (3)

--------------------------------

( ) = ( )

∴ x = 5

Substituting x = 5 in eqn 1

3x + 2y = 29

3x ( ) + 2y = 29

( ) + 2y = 29

2y = 29 – ( )

2y = ( ) ∴ Y = ( )

Step-by-step explanation:

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Answer 2

Answer:

3x+2y=29 …………….. (1)

5x-y=18 ……………… (2)

Solution : Multiplying equation (2) by 2

5x X ( ) -y X ( ) = 18 X ( )

10x –2y = ( ) …………………. (3)

Adding equation 1 and 3

3x + 2y = 29 …… (1)

+ ( ) - ( ) = ( )…… (3)

--------------------------------

( ) = ( )

∴ x = 5

Substituting x = 5 in eqn 1

3x + 2y = 29

3x ( ) + 2y = 29

( ) + 2y = 29

2y = 29 – ( )

2y = ( ) ∴ Y = ( )