Question

solving the equation a)3 (n-5)=21,n=?
b)q/4+7=5,q=?​

Answer 1

Answer:

YOU CAN USE THE FIRST EXAMPLE TO GET THE NEXT ONE

Step-by-step explanation:

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3(n-5) = 21

3(n-5) = 21 [[[[ n = 12 ]]]]

3(n-5) = 21

3n - 15 = 21

3n = 21 + 15

3n = 36

n =  

n = 12

3(n-5) = 21

First we should multiply 3 with "n" and "5".

3n - 15 = 21

We have to bring -15 to the right hand side. "-15" will change as "+15".

3n = 21 + 15

We will get 36 when we add 21 and 15.

3n = 36

Now We will have to find the value of n. So we should bring 3 to the Right Hand Side. Then divide 36 by 3.

n =  

We will get 12 when 36 is divided by 3.

n = 12

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Answer 2

a).
3(n-5)=21

(n-5)=21/3

(n-5)=7

n = 7+5

n = 12

..........................................

b).
q/4 +7 = 5


q/4 = 5-7

q/4 = -2

q = 2*4

Q=8










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