Solving the equation
Sinx+1+x^2=0
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0
Answer:
sin(x+x^2)
Step-by-step explanation:
not sure recheck with someone else thankyou<3
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Naturally the first thing I do is abuse Wolfram-Alpha. There appear to be two solutions that are the roots of x2+sinx−1x2+sinx−1 occurring near at x≈−1.40962x≈−1.40962 and x≈0.636733
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