Question

Solving the system of equations 2/x + 3/y = 3 and 3/x + 6/y = 5 we get

Answer 1

EXPLANATION.

Equation are:-

=> 2/x + 3/y = 3 .....(1)

=> 3/x + 6/y = 5 .....(2)

Let we assume that 1/x = a and 1/y = b

=> we get,

=> 2a + 3b = 3 ......(3)

=> 3a + 6b = 5 .....(4)

multiply equation (1) by 3

multiply equation (2) by 2

we get,

=> 6a + 9b = 9

=> 6a + 12b = 10

we get,

=> -3b = -1

=> b = 1/3

put the value of b = 1/3 in equation (3)

we get,

=> 2a + 3 X 1/3 = 3

=> 2a + 1 = 3

=> 2a = 2

=> a = 1

Therefore,

=> 1/x = a

=> 1/x = 1

=> x = 1

=> 1/y = b

=> 1/y = 1/3

=> y = 3

Therefore,

value of x = 1 and y = 3

Answer 2

Answer:

be 1/X =a and 1/y=B

2a+3b=3

3a+6b=5

now multiply equation 1 by two

so 4a+6b=6

now eliminate

4a+6b=6

3a+6b=5

-. -. -

a =1.

now put value of a in equation 2

3(1)+6b=5

3+6b=5

6b=5-3

6b=2

B=2/6= 1/3

1/X=1 so X=1

1/y= 1/3 so y =3