Question

soman is now 4 times as old as leela. Five years ago soman was 7 times as old as leela. find the present age of each

Answer 1

Let the Leela's age be x

Soman's age = 4x

Here's a attachment of solution

Answer 2

Answer:

Soman:40 Leela:10

Step-by-step explanation:

So, let Leela's age be x

And Soman's age as 4x

so, 5 years ago,

soman was: 4x-5

Leela was: 7(x-5)

now if we put this in an equation it all will be as

7(x-5) = 4x-5

⇒7x-35 = 4x-5

⇒7x-4x = -5+35

⇒3x = 30

⇒x = 30/3 = 10

⇒ so Leela's age is 10yrs

⇒ and soman is 4times her age which is 10x4=40yrs

I hope you understood please mark be brainiest