some amount is distributed equally among some boys. If 10 boys were more each would get ₹2 less and each would get ₹6 more if 15 boys were less. Find the amount distributed and the no. of boys
Answers
Step-by-step explanation:
Let no. of students be x and amount to each student be ₹ y
Total amount distributed us. xy
Acc. to first condition
(x+10) (y-2)= xy
xy+ 10y -2x -20 =xy
10y - 2x = 20
÷2
-x + 5y = 10...... (I)
Acc. second condustion
(x-15 ) (y+6)=xy
xy +6x -15y- 90= xy
2x - 5y =30...(II)
Adding. (I) n (II)
x = 40
Substitute x = 40 in equ (I)
y= 10
Total amount = 40× 10= ₹400
No. of students = 40
Step-by-step explanation:
let amount distributed among boys be x rupees
no. of boys be y .
from first condition ,
(x-2)(y+12) = xy
x (y+12) -2(y+12) = xy
xy +12x -2y-24= xy
12x - 2y -24 = xy
12x -2y =24
dividing both sides by 2 we get,
6x - y = 12 .............1
from second condition ,
(x+ 6) (y- 15) = xy
x(y-15) +6(y- 15) = xy
xy - 15x + 6y- 90 = xy
-15x + 6y = 90
dividing both sides by 3
-5x + 2y = 30 ................2
multiplying 1 by 2
12x - 2y = 24 ............3